D pattern in C language using only two lopps

 Hi welcome!

D pattern

   the program to print D patterns in the C language is easy. let's get deep in the program by understanding the program algorithm.

                          Algorithm of Program

step 1: intial variables a,b,c,i,

step 2: read variabl value by user in put

step 3: assign b=a and c=a-3

step 4:Repeat the step until i=a

  step 4.1: print *

  step 4.2: repeat the step until j=b

        step 4.2.1: if i=1 or i=a

        step 4.2.2: print *

        step 4.2.3: else if j=b

        step 4.2.4: print one space

        step 4.2.5: if i<=3

        step 4.2.6: variable b increament

        step 4.2.7: if i>=c

       step 4.2.8: variable b decreament

   step 4.3 : print new line 

step 5:stop

Program

#include
#include
int main()
{
int a,b,c,i,j;
printf("enter number:");
scanf("%d",&a);
b=a;c=a-3;
for(i=1;i<=a;i++)
{
printf("*");
for(j=1;j<=b;j++)
{
if(i==1||i==a)
{
printf("*");
}
else if(j==b)
{printf("*");}
else
{printf(" ");}}
if(i<=3)
{b++;}
else if(i>=c)
{b--;}
printf("\n");}
getch();
return 0;
}

Output

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