Alphbet E pattern using only two loops in C language

 Hello welcome!

program to print E pattern in C language using only two loops. to understand better lets see the algorithm of the program 

                    Algorithm of program

step 1:start 

step 2:initial variables i,j,a,b

step 3:Read a value in a variable 'a'

step 4:assign b=(a/2)+1

step 5:repeat the step until i=a

  step 5.1:print *

  step 5.2:repeat the step untill j<a

     step 5.2.1:if i=1 or i=b or i=a

     step 5.2.2:print *

     step 5.2.3:else

     step 5.2.4:print *

step 6:print new line

step 7:stop

Program

#include<stdio.h>

#include<conio.h>

int main()

{

int i,j,a,b;

printf("enter a number");

scanf("%d",&a);

b=a/2+1;

for(i=1;i<=a;i++)

{  printf("*");

for(j=1;j<a;j++)

{
if(i==1||i==b)

printf("*");

}

else {printf(" ");}}

printf("\n");

}

getch();

return 0;

}

Output