C program to print B pattern using only to for loops in easy way

 Hi there!

    The program to print B pattern in the C language is easy. To understand the structure of the program let's see the algorithm of the program

                                   Algorithm of program

step 1: Start

step 2: Initialize variables a,j,b,i

step 3: Read a from user

step 4: b=(a\2)+1

step 5:   Repaet the step until i=a

step 5.1:            print one space

step 5.2:              print *(star)

step 6:   Repeat the step until j=b+1 

step 7:   if i=1 or i=b or i= a

step 7.1:     if j=b+1

step 7.2:             print one space

step 7.3:        Else

step 7.4:                print *

step 7.5:         if i not =1 and i not = b and i not = a

step 7.6:                      print *

step 7.7:           Else 

step 7.8:                     print one space

step 8: print new line

step 9: Stop

Program

#include
#include
int main()
{
int a,j,i,b;
printf("entera a number");
scanf("%d",&a);
b=(a/2)+1;
for(i=1;i<=a;i++)
{
printf(" ");
printf("*");
for(j=1;j<=b+1;j++)
{
if(i==1|i==b||i==a)
{if(j==b+1)
{printf(" ");}
else
{printf("*");}}

if(i!=1&&i!=b&&i!=a)
{
if(j==b+1)
{printf("*");}
else{printf(" ");}
}
}
printf("\n");}
getch();
return 0;}

Output

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