Hello there!
Welcome to our blog. in this blog we will see how to write code to check the given number is a prime number or not. believe the code is very simple and clear.
Algorithm of the program
Firstly, we will see the algorithm to acquire awareness about the program i.e, how the program will work a step by step process.
The steps are involved in algorithm 6.
There are:
Step 1: Start
Step 2: Initialize variables
flag<-1
i=2
Step 3: Read n from the user.
Step 4: Repeats the steps until I>(n/2)
4.1 If the reminder of n÷i equals 0
flag=0
Go to step 5
4.2 i=i+1
Step 5: If flag=0
Display n is not prime
else
Display n is prime
Step 6: Stop
To better understand the program take look at the flow chart program here is the flow chart
Flowchart of program
![]() |
| flow chart of the program |
Its program time lets see the program
Program
#include
#include
int main()
{
int i, a, b = 0;
printf("enter a number");
scanf("%d", &a);
for (i = 2; i <= a/2; i++)
{
if (a % i == 0)
{
b = 1; break;
}
}
if (b == 1) {
printf("given number not prime");
}
else {
printf("given number prime");
}
return 0;
}
Output
![]() |
| output of program |
ok, if you have any doubt feel free to contact us. if you want any program in C language please comment we will try my level best.
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